Lineare Algebra Beispiele

$\frac{1}{93} \cdot \tan (0.229) + \frac{1}{93} \cdot \tan (\frac{π x}{118}) + \frac{1}{93} \cdot \tan (0.346) + \frac{1}{93 \sin (\frac{2 (π x)}{118}) + 14 \tan (\frac{π y}{101}) - \frac{1}{\frac{1}{14} \cdot \sin (\frac{2 (π y)}{101}) + \frac{1}{93} \cdot \tan (\frac{π x}{118})}} = - 0.037$ , $\frac{1}{93} \cdot \tan (0.35) + \frac{1}{93} \cdot \tan (\frac{π x}{77}) + \frac{1}{93} \cdot \tan (0.53) + \frac{1}{93 \sin (\frac{2 (π x)}{77}) + 14 \tan (\frac{π y}{66}) - \frac{1}{\frac{1}{14} \cdot \sin (\frac{2 (π y)}{66}) + \frac{1}{93} \cdot \tan (\frac{π x}{77})}} = 89.77$

Schritt 1

Das Gleichungssystem ist kein lineares System.

$\frac{1}{93} \cdot \tan (0.229) + \frac{1}{93} \cdot \tan (\frac{π x}{118}) + \frac{1}{93} \cdot \tan (0.346) + \frac{1}{93 \sin (\frac{2 (π x)}{118}) + 14 \tan (\frac{π y}{101}) - \frac{1}{\frac{1}{14} \cdot \sin (\frac{2 (π y)}{101}) + \frac{1}{93} \cdot \tan (\frac{π x}{118})}} = - 0.037, \frac{1}{93} \cdot \tan (0.35) + \frac{1}{93} \cdot \tan (\frac{π x}{77}) + \frac{1}{93} \cdot \tan (0.53) + \frac{1}{93 \sin (\frac{2 (π x)}{77}) + 14 \tan (\frac{π y}{66}) - \frac{1}{\frac{1}{14} \cdot \sin (\frac{2 (π y)}{66}) + \frac{1}{93} \cdot \tan (\frac{π x}{77})}} = 89.77$